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4.9x^2+15x=30
We move all terms to the left:
4.9x^2+15x-(30)=0
a = 4.9; b = 15; c = -30;
Δ = b2-4ac
Δ = 152-4·4.9·(-30)
Δ = 813
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{813}}{2*4.9}=\frac{-15-\sqrt{813}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{813}}{2*4.9}=\frac{-15+\sqrt{813}}{9.8} $
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